x^2+2x+(sqrt(6x))=17

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Solution for x^2+2x+(sqrt(6x))=17 equation:


Simplifying
x2 + 2x + (sqrt(6x)) = 17

Remove parenthesis around (6x)
x2 + 2x + (qrst * 6x) = 17

Reorder the terms for easier multiplication:
x2 + 2x + (6qrst * x) = 17

Multiply qrst * x
x2 + 2x + (6qrstx) = 17

Reorder the terms:
(6qrstx) + 2x + x2 = 17

Solving
(6qrstx) + 2x + x2 = 17

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '-2x' to each side of the equation.
(6qrstx) + 2x + -2x + x2 = 17 + -2x

Combine like terms: 2x + -2x = 0
(6qrstx) + 0 + x2 = 17 + -2x
(6qrstx) + x2 = 17 + -2x

Add '-1x2' to each side of the equation.
(6qrstx) + x2 + -1x2 = 17 + -2x + -1x2

Combine like terms: x2 + -1x2 = 0
(6qrstx) + 0 = 17 + -2x + -1x2
(6qrstx) = 17 + -2x + -1x2

Divide each side by '(6rstx)'.
q = 2.833333333r-1s-1t-1x-1 + -0.3333333333r-1s-1t-1 + -0.1666666667r-1s-1t-1x

Simplifying
q = 2.833333333r-1s-1t-1x-1 + -0.3333333333r-1s-1t-1 + -0.1666666667r-1s-1t-1x

Reorder the terms:
q = -0.3333333333r-1s-1t-1 + 2.833333333r-1s-1t-1x-1 + -0.1666666667r-1s-1t-1x

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